Hi Doug, Like we were talking in the other thread, I take a 2” piece of 16 gauge wire and just loop the thing from the exciter lug to the battery post on the alternator (I wouldn’t do this on someone else’s rig, but have done many, many setups of my own). The regulator stays “hot” all the time. In essence, this makes it truly a “one wire” alternator, as far as the electrical system goes, but the darned thing is always “On” and is never isolated from battery voltage. You mentioned that the field circuit would drain the battery. On an externally regulated alternator, this is certainly true. But, on an internally regulated alternator (I’m talking GM), the exciter circuit does not provide field current in any way whatsoever and the battery does not provide any field current to the alternator in any form. If this were the case, the darned alternator would stop charging if you removed the battery. It doesn't, take the battery out of the picture and the alternator just keeps right on a doin' it's job of maintaining system voltage and providing field current as needed. The exciter current only turns on the regulator gate and takes the alternator out of isolation. Yes, by hot-wiring the exciter, the regulator stays on all the time, but so what? There is always power at the light switch too. Since the regulator uses the alternator's own induced voltage as a field voltage source, without rotor rotation, there is absolutely no draw thru the field circuitry anyway. I would almost bet that there is more of a drain thru the dirt/dust between the two battery posts than the miniscule current that is holding that regulator gate open. Just my view, even tho it might be somewhat up-side-down. :>) Allan
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