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John Deere Tractors Discussion Forum
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12V battery conversion to 6V wico problem....

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Jim

07-24-2004 07:30:40




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12V battery with alternator has been running on this tractor for over 10 years. Burned up the coil. Put a new coil in last year, and burned it up also. Im having a problem getting the voltage down to an acceptable 8-9 volts. I have a fresh rebuilt Wico XB, dont want to ruin this one. I have a ballast resistor in line to the coil. 1.5 ohms. I get a reading of 11.5 volts at the coil with tractor running. I installed JD part AA5791R, 2.5 ohms, and still get 11.5 volts at the coil. Im using a new analog meter that tests ok on my other tractors electrical wiring. I installed a 3 ohm resistor and the tractor would not start. I have unhooked everything/alternator and still get the same results. How do I get the voltage down? What am I doing wrong? I have tried to get a drawing posted here of how my wiring is hooked up, but no such luck. I will email a drawing to anybody who would like to maybe assist me with this. I have been working on this for over a week, and have tried many things, and about ready for the booby hatch. I just cant seem to get it right. I appreciate all your help. Thanks. Jim.

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John T

07-24-2004 07:52:45




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 Re: 12V battery conversion to 6V wico problem.... in reply to Jim, 07-24-2004 07:30:40  
Jim, if you wanna e mail me what you have, I will try n help you out. If you run the voltage too high and pass more coil current through that Wico coil, it overheats as you realize. When they used that 6 volt XB distributor on 12 volts, they added a block looking series ballast resistor in line with the switched ignition wire from the ign switch down to the power input terminal on the Wico.

When you measure the non running voltage on the wico input terminal, it has to be with the points CLOSED or it will still read the full 12 volts you know, regardless if any ballast or its size.

The simple circuit is from the load side of the ammeter,,,,,to the Ign switch BAT side input,,,,, ,out the IGN terminal which is HOT WHEN ON,,,,, ,to and through the voltage dropping Ballast,,,,, ,,to the Wico.

The Wico has another lil internal resistor also ahead of the coil. Ideally, with the points closed, the ohms value of the external ballast would be equal to the Wico's total (Its coil + internal resistance) that way it acts as a 50/50 voltage divider, dropping 6 leaving 6 at the Wico. The resistor values you mentioned ought to get you in the ballpark, however, be sure to make non runnign measurements when the points are closed.

Let me know, Good Luck n God Bless

John T jmn50@msn.com

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