Tim..... ...I appreciate yer willingness to re-design a 70yo ignition system that so many don't seem to understand. (incuding you) And the principal reason for the "infamous ballast resistor" was (are you ready for this?) weaksister 6-volt batterys. They didn't have die-hards back in 1930's. Batterys are results of chemical reactions, chemical reactions are slowed down by COLD temperature. Therefore, Ford used a ballast resistor to INCREASE SPARKIES when it was COLD for easier starting. Simple, eh? Gitt this straight, its called a ballast resistor because its resistance changes depending on INTERNAL temperature. It is designed to do that. And do all that auto-magically. Somewere, I have a spec-sheet on the "infamous ballast resistor" that sez the MINIMUM resistance is 0.4-ohms and the MAXIMUM resistance is 1.7-ohms. In the electronics trade that is known as POSITIVE TEMP co-efficent. But after about 2-minutes of engine runnin' the heated-up resistance is about 1.4-ohms. You need LAB-GRADE elecronic resistance measuring devices to accurately measure those LOW value resistances. But surprizingly enuff, even a $10 el-cheepo voltmeter is plenty accurate to measure the VOLTAGE DROP cause by that hard to read resistance. As for WATTS rating of the ballast resistor, I believe it is 50-watts. This is very typical 2.5 times safety factor. You doubt? Typical ignition draws about 3-amps. Since POWER is as simple as PIE (Power=I (amps) times E (Electro Motive Force) nutter name for volts) Simple math calculations: P=3-amps times 6-volts = 18-WATTS. Safety factor 2.5x18=45-watts. Waddaya know? USE 50-watts design factor. Simple, eh?..... ...Dell, retired electronics engineer and certified CAL-LAB engr with 50yrs experience
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