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Ford 9N, 2N & 8N Discussion Forum
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2N electrical

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pilot199

04-15-2006 13:21:43




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Looking for help again on my '47 model 2N.
I rewired the ignition for to try to correct the 12vdc conversion but when I hook up the battery the terminal block resistor & ballast resistor get pretty hot.

The schematic in "myoldfords.com" didn't quite match up with what I have on the tractor. The present 12vdc alternator only has 1 lead going into it!

This is the way I have it wired presently: RIGHT HAND TERMINAL BLOCK POST
-12VDC Battery from ammeter -one side of key switch
-lead to alternator

LEFT HAND TERMINAL BLOCK POST
-other side of key switch
-lead to ballast resistor then to coil

Does this sound correct.
I know it should be simple because I don't even have lights on the tractor.

Any help is appreciated.

Happy Easter

Gary
Baton Rouge

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Dell (WA)

04-15-2006 14:08:00




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 Re: 2N electrical in reply to pilot199, 04-15-2006 13:21:43  
Pilot..... ..you write....."when I hook up the battery the terminal block resistor & ballast resistor get pretty hot"..... ..yep, resistors gitt HOT. (burnie, burnie)

Howsomevers; resistors should ONLY gitt hot when the ignition switch is ON.

You write..... ."This is the way I have it wired presently:"

RIGHT HAND TERMINAL BLOCK POST
-12VDC Battery from ammeter
-one side of key switch
-lead to alternator

LEFT HAND TERMINAL BLOCK POST
-other side of key switch
-lead to ballast resistor then to coil

WRONG..... ...WRONG..... ...WRONG!!!..... ..you only list 2-terminals. The terminal board is a 3-terminal device, in the form of a "T".

The top of the "T"-form of terminal board supports the "infamous ballast resistor". It should be intuitively obvious that oneside of the ballast resistor must go directly to the 1-terminal ontop of the squarecan ignition coil. We'll conviently call that the RIGHT terminal. Since oneside of the ballast resistor is connected to the RIGHT terminal, logically that implies that the other side of the ballast resistor is across the top of the "T"-form connects and connects to the LEFT side of the "T".

Since the OEM ignition switch is a 2-wire/terminal device, it should be intuitively obvious that eather switch connection will perform the ON function when connected to the LEFT side of the "T"-form to the ballast resistor.

For the ignition switch to function, it should be intuitively obvious that it must have a source of BATTERY VOLTS. And surprizingly enuff, the BOTTOM of the "T"-form is conviently connected to a common BATTERY source (usually the BATT terminal of the BIG starter switch) thru the ampmeter.

Usually, the alternator/generator OUTPUT connects to the BIG BATT stud of the starter switch/solenoid..... ....Dell

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pilot199

04-15-2006 15:05:37




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 Re: 2N electrical in reply to Dell (WA), 04-15-2006 14:08:00  
Thanks Dell, I think I've got it now. I'm getting confused by what the old manual shows but that was for a 6 vdc system.

Here's the way it is now:

(Using the "T", I label them left, right & bottom)

BOTTOM TERMINAL POST
-12vdc coming from ammeter
-one side of key switch

LEFT TERMINAL POST
-other side of key switch

RIGHT TERMINAL POST
-lead to coil(this goes thru the original ballast resistor mounted on batt. tray)


QUESTIONS:
1-is the above correct?

2-do I still need the ballast resistor on batt. tray?

3-If I tie in the alt. lead (there's only 1) to the big batt. stud won't the alt. field draw 12vdc even when turned off?? If so, could it be attached to the right terminal post?

Sorry to keep bugging you; I appreciate your help.

Gary

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