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Tool Talk Discussion Forum

Log Splitter Hydraulics ???

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Bruce a.

10-09-2003 18:11:18




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Going to build a new log splitter. The current stuff I have laying around is a 5X24" ram, 6.5hp briggs engine, no pump yet. My question...Will a 13.6 gpm barnes pump give ample power and cycle time for this ram, or should I opt for a 16 gpm. Then I'll assume a 8 hp or larger motor will be needed for this pump. What will be my best option for this ram/engine combo if even possible???? Thanks for input!

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Fred OH

10-13-2003 06:06:06




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 Re: Log Splitter Hydraulics ??? in reply to Bruce a., 10-09-2003 18:11:18  
I didn't get involved in all the calculations, I just started asking questions as you are. I have a 4 x 24" cylinder with a Briggs 5 HP @ 11 gpm John Barnes 2 stage pump and my cycle time was either 14 or 17 seconds. I put a gage on it and most wood split at around 700 lbs. pressure...probably not out of the first stage of the pump. I did stick it once and it lifted the relief valve at around 2300 gage pressure. In my opinion...it's just as good as a factory built splitter. I would say judging from mine that a 11 gpm will work for sure in your case with a 6.5 hp engine...even if it is a little tired. Fred OH

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Tom R

10-13-2003 12:23:58




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 Re: Re: Log Splitter Hydraulics ??? in reply to Fred OH, 10-13-2003 06:06:06  
Pretty darn good guess on the unloading pressure on the high volume stage Fred.

The actual factory setting for the unloading valve is usually about 650 PSIG. With a settable unloading range on most of the pumps in the 400 to 900 PSI range.

If anyone wants more information on the two stage Barnes pumps (including the performance curves) here is a link that will get you a PFD download for the Barnes two stage pumps

http://www.hbus.haldex.com/Distributor/Catalogs/HI_LO_PG.pdf

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hjp

10-11-2003 16:41:25




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 Re: Log Splitter Hydraulics ??? in reply to Bruce a., 10-09-2003 18:11:18  
all seem to have the right info,however use the largest size of hose/fittings,transfer of the oil from the ,tank,filter,pump,valve,cyclinder and back needs to match the over all flow,I have seen to many home built units many better than bought ones get "choked" up and when there re-plumbed do produce the right speed and pressures.forceing 13gpm through a 1/4,3/8 line reduces your over all pressure and your not going to happy !!!!

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KURT (mi)

10-10-2003 16:46:10




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 Re: Log Splitter Hydraulics ??? in reply to Bruce a., 10-09-2003 18:11:18  
Being a hydraulic guru for years, Use this formula: Horsepower required = GPM X pressure /1460. So You can see that if you have 13.6 gallons per minute then you would need an 18 Horse motor to drive the pump at 2000 psi. I am assuming that the pump is rated at 1800RPM. A 6.5 HP briggs engine will let you use a 4GPM pump at 3600 rpm on the motor and system pressure of 2000psi. 2000psi will give you 39,200lbs of force on the piston of the cylinder. Hope this helps. BTW: a barnes gear pump is not a variable volume pump. Also keep in mind that a gas engine HP is rated at 3600rpm usually.

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treeboy

10-10-2003 16:38:26




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 Re: Log Splitter Hydraulics ??? in reply to Bruce a., 10-09-2003 18:11:18  
nice job, tom... i too vote for a two stage pump & a return auto valve detent ( only way to go) ALSO put an inline oil filter on prior to the pump. i used an old air tank from a large forklift brake system for my oil tank, purchased the tank breather mech. also.. i converted a tractor pto log spliter into a selfcontained on wheels,ball hitch with the splitting table approx. 2 feet high so i don't bend over while operating...

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Tom R

10-10-2003 06:18:54




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 Re: Log Splitter Hydraulics ??? in reply to Bruce a., 10-09-2003 18:11:18  
Most Log splitters using small engines as a power source will use a two stage pump. Using low pressure/high volume stage to advance and retract the cylinder (to get reasonable cycle time) and then will switch to a low volume high-pressure stage when the ram meets a restriction to provide the splitting power.

Most commercial small engine driven log splitters are rated at 20 tons, so lets assume you are shooting for a 20 Ton unit.

Force = 20 ton *20000 lbs/ton
Force = 40,000 pounds
If we work around your cylinder as a given we will find the following

Cylinder area =PI * radius squared
Cylinder Area=3.1416*2.5^2 =19.635 Sq inches

So if PSI= Force/area 40,000 pound /19.635 sq inches = 2037 pounds per square inch

Is your cylinder rated for at least 2000 PSI of pressure?

HP=GPM *PSI * 0.0007
GPM = HP/(PSI *0.0007)
If you use a single stage pump then,
4.5 gallon per minute is the max you can pump with 6.5 HP at 2037 PSIG
5.6 gallon per minute is the max you can pump with 8 HP at 2037 PSIG

and I don't think you would be happy with your cycle times.

Here is a good place to look at hydraulic components

Link

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