Re: Re: Re: High low battery charge settings for a '47 Farmall H

Posted by Geoff Gauger on January 21, 2002 at 10:30:08 from (12.155.240.196):

In Reply to: Re: Re: High low battery charge settings for a '47 Farmall H posted by Mike ISW on January 18, 2002 at 16:07:24:

The cutout is older technology, it has two components inside, a wire wound resistor and a solenoid. The resistor is in the ground circuit for the field and will not be used with the four
position light switch. With lights, a similar 2.8
ohm resistor is mounted on the switch. Depending on the switch position, the field is either grounded direct to the frame or through the resistor to the frame. A stronger ground means higher generator output. Without lights, the field is either grounded to the generator case directly or through the resistor in the cutout and then to the case. Same effect as with the light switch. The generator will have four terminals, G,F, BAT, and L.
The solenoid in the cutout simply breaks the circuit to the battery when the engine is not running to keep the battery from discharging.

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