Yep, cuz the result of two resistors in paralell is less then either, so if say a 90 ohm is in paralell with a 10 ohms the result is
90 x 10 / 100 = 9 ohms
The lowered resistance should then allow sufficient current to excite the alternator and the LED in paralell with the resistor makes up a a current divider, so when the alternator isnt producing voltage the current out of the switch will flow thru thAT current divider on its way to the alternator and lite the lamp assuming its sufficient enough current..... Buttttttttttt then when the alternator gets excited there will be too low voltage across that LED and it should go out.......
I think thats right?? The wife is callin me to breakfast and Im in a hurry lol if Im all wet (wont be first or last time) Bob can correct my errors........
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