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Re: My Electrical Stupidity


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Posted by Janicholson on August 23, 2010 at 12:04:28 from (199.17.6.223):

In Reply to: Re: My Electrical Stupidity posted by JMOR on August 22, 2010 at 17:30:50:

I have no issue with the concept of AC current being transferred (in some cases with apparent no resistance) through a cap. The reality that we speak of, and which Teddy has corectly identified is that the capacitor in a point/condenser style ignition acts (at the spark extenguish point) as a resonator, passing low frequency charge into and out of the plates as it absorbs and returns the EMF of the collapsing coil magnetism. As this dwindles to nothing, resistive/reluctance decay) the points, or a transistor, can again close without radical spark. We may be arguing from the same point with regards to the reality of AC current and electrons, but electrons do not go through a cap.
From on line source:

The current i(t) through any component in an electric circuit is defined as the rate of flow of a charge q(t) passing through it, but actual charges, electrons, cannot pass through the dielectric layer of a capacitor, rather an electron accumulates on the negative plate for each one that leaves the positive plate, resulting in an electron depletion and consequent positive charge on one electrode that is equal and opposite to the accumulated negative charge on the other. Thus the charge on the electrodes is equal to the integral of the current as well as proportional to the voltage as discussed above. As with any antiderivative, a constant of integration is added to represent the initial voltage v (t0). This is the integral form of the capacitor equation,[12] Jim


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