Posted by sws55 on January 22, 2011 at 06:57:10 from (173.29.40.52):
In Reply to: C.G. of an M? posted by CenTex Farmall on January 21, 2011 at 19:37:27:
If you know your tractor's total weight, the weight on the front axle and the length of the tractor's wheel base you can calculate the static center of gravity.
(Front axel weight divided by the total tractor weight) x the wheel base = distance from rear axel to the center of gravity.
i.e. if: WB is 100 inches total weight is 6000 lbs and front axle weighs 1500 lbs
(1500lbs / 6000 lbs) x 100 inches = 25 inches ahead of the rear axel.
An easier way to think of it is the percentage of the weight on the front axel can be multiplied by the lenght of the wheelbase to find the CG.
If 25% of the weight is on the front axle the center of gravity is 25% of the wheel base ahead of the rear axle.
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