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Re: Farmall 1456 wiring question


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Posted by Owen Aaland on May 05, 2012 at 13:10:36 from (216.47.35.176):

In Reply to: Farmall 1456 wiring question posted by MaverickM23 on May 03, 2012 at 11:21:52:

You are correct. Wiring all four together will put battery voltage on both side of the charge indicator light and it will not light up. Besides that it is bad practice because it takes both the resistor and the light bulb out of the circuit and you lose their protection from having excess current in the excite circuit of the alternator if a problem should develop in the battery wire to the alternator.

When I posted the original comment it was in reply to not being able to get the alternator to start to charge. He also mentioned that his wiring was in bad shape and some of the wires may be broken.By connecting all the wire together there was a much better chance that he would at least get power to the alternator for the excite terminal.

The wiring for the 10SI excite circuit should have power coming both the the light bulb and through the resistor. The resistor should be there so that the alternator will start to charge even if the light bulb is bad. Your method of connecting the #4 wire to either or both of the F and #2 wires and then connecting them to the #1 terminal at the alternator and adding a jumper between the battery output terminal and the #2 on the alternator is probably the best you can hope for using the original harness.

Another unfortunate side effect of switching from a 10DN to a 10SI is the warning light will not be as bright with the newer alternator. The 10SI rotor only draws half the amps as compared to the 10DN. The higher resistance in the rotor winding will cause the light to be dimmer.

It is too bad the IH did not use the same wiring system as as shown in the Delco Remy diagram. It would then be simple matter of connecting the #4 wire to the #1 terminal on the alternator and the the #3 wire to the #2 alternator terminal.


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