Janicholson said: (quoted from post at 18:42:44 03/02/12) Horse power is only how fast a specific task can
get done. Pull a hay wagon weighing 2000 pounds
up a 10% grade for one mile in 6 minutes (assumes
full rated power on the engine/motor). It can be
done by any power source with that rated horse
power.
Thus a tiny MC racing engine, or a 2 cylinder JD.
are equal. It certainly requires different
gearing to have it take place, but the power is
equal.
The difference between them will be in the
capability to continue to produce that level of
power output. Unless force fed massive cooling
air, the MC engine would seize. If it made it
(with extra air) it would not do it 20 times in a
row. It is designed to have to make 15 horse
power at 80 MPH for a long time, and 150 HP for 10
seconds at a burst.
The tractor engine can do it for 10,000 hours.
Jim
See, I don't agree here. In theory, a little electric motor that spins at ridiculously high RPM could make as much HP as a 40 HP JD. Say it has only 1 ft/lb of torque, but spins a 210,000 RPM. According to the formula I used 40 HP = (1 * X) / 5252 where X is RPM. 1 ft/lb of torque will never be enough to pull a plow now matter how fast it spins or how low it's geared, right? I'm guessing this would also be true for any motorcycle engine making 40 Hp.
This post was edited by flyingace at 15:26:08 03/03/12.
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