Posted by JD Seller on December 25, 2012 at 20:46:49 from (208.126.196.144):
In Reply to: Corn silage questions posted by Jacksonduper on December 25, 2012 at 20:03:24:
Jackson: The average yield of corn silage in good corn is usually about 15-20 tons per acre.( link to article about it below)
On how much you would feed. A brood cow will consume 2.5-3% of her body weight on a Dry matter basis daily. So assume a 1200 Lbs. cow.
1200 x 2.5% = 30 lbs
65% moisture corn silage would be 30 lbs/.35 = 85.7 lbs of silage per head per day.
Now you would not want that all to be corn silage. She does not need that much energy. So I would cut that ration with dry hay, straw, or even corn stalks. If you have a TMR wagon then it is easy to just make an ration that would be about half corn silage and half hay/stalks/straw.
If you are feeding it in bunks without a feed wagon and are free choice feeding the hay. I would figure about 45-50 lbs of silage per head per day. More when cold less when warm.
So your 20 head would eat about a 1000 lbs per day.
You need to feed at least 1-2 inches a day off the face of silage to keep ahead of spoilage. Feeding a 1000 lbs a day in a 8 ft. silage bag would be feeding about 6 inches per day. So you would easily keep in front of any spoilage in an 8 foot bag of silage. An 8 foot silage bag usually holds about a ton of silage per foot of length. So a 250 ft bag would hold about 250 tons of silage.
Cost to put up a 250 foot bag would be about $8-10 per ton when figuring all cost: Chopping, the bagger, and the bag itself.
I would just call and ask some one that does custom chopping in your area about the cost to put up a 8 ft. diameter 150 foot long bag. That would easily feed your cattle over a winter. If they only have a 10 ft bagger then cut the length back to 100 ft. You would only feed about 4 inches off the face each day but that would still be ahead of spoilage.
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