If I take the 33,000 lbs., and divide it by 60, I would get 550, which is what 1 hp has the value of raising in one second, one ft. Now if I divide 550 by the gallon weight,(8.3 lbs.),I get 66.3, multiplied by the hp. of the tractor, gives me 3646, my lift figure in feet. This should be the number 55 hp would raise 8.3 lbs or one gallon of water in one second. Now if I take my lift result of 3646 and multiply it by 10 seconds, my lift would be 36,460 feet in 10 seconds, right?
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Today's Featured Article - The Ferguson System Principal An implement cutting through the soil at a certain depth say eight inches requires a certain force or draft to pull it. Obviously that draft will increase if the implement runs deeper than eight inches, and decrease if it runs shallower. Why not use that draft fact to control the depth of work automatically? The draft forces are
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