Posted by Fatamus on November 14, 2014 at 08:43:57 from (216.137.222.198):
In Reply to: magneto posted by Fatamus on November 14, 2014 at 07:52:41:
How condensers/capacitors work. A condenser is also called a capacitor and how they work is really easy to understand. Unlike lead acid batteries which generates a charge via chemical reaction a condenser just holds a charge in a non-conductive material.
How it holds a charge is quit interesting. If we looked inside a condenser we could find a number of different materials for different applications. First, let's imagine taking a condenser and cutting it in half lengthwise. We would see layers of two different materials; it could be sheets of copper or silver with glass, air or even film spacers between them.
As a charge is passed by the leads of copper or silver some of the charge/electrons is actually stored in the glass or film and can be released when needed.
I have a pic to help understand
this may help too
by Bruce (VA)
PostPosted: Fri Oct 31, 2014 1:23 pm Post subject: Re: hard starting & no power Reply to specific post Reply with quote
The 6 or 12 volts produced by a battery will not produce a spark in a combustion chamber. But, if you put 6 or 12 volts into a coil, you can get 22kv out of it. That produces the spark.
When the points are closed, the coil is "energizing". When the points open, the magnetic field in the coil collapses & it produces a 22kv spark at the plugs.
Technology & materials being what they were in the 30's, that square coil would melt if it ran on much more than 4 amps for any length of time. (see tip # 38 for an example). In order to get a hot spark at the same time the starter was drawing max current from the battery, a ballast resistor was added in the ignition circuit. What that did was add about .3 ohms of resistance in the circuit, added to the 1.5 ohms of the coil. That got you 3.5 amps or so at start up. As the voltage increased when the engine was running to about 7.5 volts, the resistor heated up, adding more resistance in the circuit. 1.0 ohms hot, plus 1.5 ohms of the coil got you down to 3 amps or so to keep from melting the coil. The same rule (actually, Ohm's Law) applies to a 12v circuit. I= E/R. Current equals voltage divided by resistance.
Your 6v coil had some fixed resistor of unknown value to keep it from melting. But, because it was a fixed resistor, it also reduced current needed for a cold start.
Need more info? Google "Kettering Ignition".
This post was edited by Fatamus at 13:03:59 11/14/14 2 times.
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