Thanks for the kind words. Okay, here's my best recollection but no warranty as its been a longgggggggg time ago lol. Also, Im NOT a Ford man, I don't know that much about them so cut me some slack lol
I think your thinking right !!!!!!!!!!and Im thinking if the shunt were open the current would pop the galvo windings (very small wire) instantly and the meter wouldn't move at all????????????
Some ammeters, and I "think" some on old Fords, used an induction type of ammeter where the battery cable simply passed by the meter with no in and out or actual series connections. True, many ammeters are shunt type with a low resistance shunt in parallel with a high resistance galvo type of meter movement. That served as a current divider where most current passed through the low resistance shunt, while a small fraction of current had to actually flow through the small galvo assembly to deflect the needle. Id think if the low resistance shunt (whats designed to carry most of the current) was bad/open normal current would then be so great it would burn the galvo windings open instantly.
In this case it appears the needle and galvo is functioning as the needle still moves and again I think if the shunt was open the galvo winding would burn open instantly.
An "ideal" ammeter is ZERO resistance while an "ideal" voltmeter has infinite resistance. An ammeter is NOT supposed to be a load that affects the load current readings which is why its like ZERO ohms resistance which is why if I recall correctly any shunt would be very low ohms so the current divider allows most current through it with only a small fraction having to pass through the small tiny wire galvo windings
Maybe Bob or some Ford men can correct me if my memory is wrong!!!!!!!!!!!!!!!!!!!!!!
Does this help or answer your question or make any sense at all lol
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