Posted by Texasmark1 on March 01, 2017 at 16:29:54 from (172.243.86.199):
In Reply to: Tractor/Generator size posted by martin reece on February 28, 2017 at 11:38:42:
45kVA output of the generator, figure 75 % efficient, requires 45/.75=60 kVA load on power source. At 746w/hp, 60/.746 = 80 hp input at the shaft at max rated output. Half load would be 40 hp. Probably enough kinetic energy in the system to handle starting surges of 10% or so.
Course watts are VA at a power factor of 1...voltage and current in phase, like a resistive load. So, as the generator's load becomes more inductive running uncompensated heavy starting/running motors, the PF would drop and that would skew the drive requirement.
Part of my house in on a Generac Standby gen of 11kw rating. Engine for that gen is 530cc 18 hp @ 3600 rpm rating. With that ratio, for 45 kva would require 45/11 = 4 x 18 hp = 73.6. Looks like my "guesstimate" of 80 is where it is.
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