If you have a plow that is properly sized for the tractor it will work fine. Implement dealers used to like to sell big iron, so they'd sell the largest plow a tractor could pull and extra weights so a tractor would lug in a low gear with a lot of smoke and tire slippage (10 to 20 percent tire slippage instead of 5 to 10 percent). You could actually get more done on less fuel with a smaller plow moving at 5+ MPH with half the tire slippage, but that was far less impressive than pulling the bigger plow.
Often it comes down to estimating how much time you have to complete a job and then using equipment that can get the job done in that amount of time. A rough guide for how many acres can be covered per hour is: "Width in feet" multiplied by "Speed in miles per hour" divided by ten = acres per hour. (use actual ground speed allowing for tire slippage) This works out to roughly 70 percent efficiency, tillage efficiency will be a little better than 70 percent, harvest and planting will be below 70 percent efficiency.
If your MF135 can pull 3-12 plow at 3.5 MPH actual ground speed: (3 bottoms x 12 inches/12 inches per foot) X 3.5 MPH divided by 10 = 1.05 or about 1 acre per hour. 10 acre divided by 1 acre per hour = 10 hours to plow your 10 acre field.
If your 756 can pull a 4-16 plow at 4.5 MPH: (4 bottoms x 16 inches/12 inches per foot) X 4.5 MPH divided by 10 = 2.4 acres per hour. 10 acres divided by 2.4 acre per hour = 4.2 hours
If you really want to, you could calculate the cost of fuel saved using the smaller tractor verses your additional labor cost, but if you enjoy the extra seat time plowing, it does not matter. Have fun!
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