I am not commenting on the usefulness of this, however, to your question:
Lets assume you have a rear end (car or truck) with a 3:1 gear ratio. At 540 RPM your PTO would turn the axle shafts at 180 RPM (540 / 3). Now lets use a pair of 30" tall tires. For each revolution of the tires you would move 7.85 ft (2.5 ft x 3.14 (pie)). Driving the tires at 180 RPM would result in a speed of 1413 ft/min (180 rev/min x 7.85 ft/rev). I will leave it to the reader to convert 1413 ft/min to 16 MPH.
Now, 16 MPH will not set any speed records. Mounting a set of 60" tall tires would result in double the speed, 32 MPH. This of course still requires an engine speed to drive the PTO at 540 RPM. Changing the rear end ratio to 2:1 (if you can find one) and using 60" tires would result in 48 MPH. This would allow a reduction of engine speed, for a more relaxed drive.
Now, HP increases as speed increases, doubling the speed requires double the HP. Also, consider how you will be starting from a stop with the tractor geared for 48 MPH. Does your PTO have a low gear you can use for starting and then shift up...?
Work it out on long these lines and report back....eh
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