Posted by sotxbill on August 01, 2021 at 19:12:52 from (104.5.24.112):
In Reply to: Mileage question posted by rrlund on August 01, 2021 at 07:16:45:
Yes and no... The most efficient rpms for an engine will always at or below maximum torque. So... gearing the car to go as fast as possible with the engine close to max torque figure will generally get you there. And then factor in bearing drag, wind drag, and you seem to find that 40 to 60 mph are the sweet spots with the overdrive transmissions also based on gearing. Poor gearing can lower the sweet spot to 42 mph on a 2004 chevy impala as tested. engineers dont like to run the vehicle at its max efficiency because, the lest little hill or wind gust will slow the car down dramatically, so they tend to design it back down a bit for a fair reserve. When od came out, it immediately added around 3 mpg to most all vehicles, and extended engine life by 50%. Further aerodynamic designs, less weight, more gears to keep rpms down, electronic high voltage ignitions, computer controlled timing and mixture control, have allowed even another 6 mpg in cars. Once you exceed max torque, your trading rpm for power, and you loose mpg's exponentially. see https://www.mpgforspeed.com/ This uses wind drag only as a factor. With wind drag, if you double the hp, you will increase top speed by only 25% but increase fuel consumption by 125%... old rule of thumb. remember the fast the engine turns, the more power is lost of stopping the pistons going down, and then sending them back up. Where a rotary engine does not suffer this problem as much. Cam chains also suffer from the change of direction losses.
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