Re: Reason for my electronics 101 question

Posted by Bob on October 26, 2006 at 07:25:38 from (69.178.229.154):

In Reply to: Reason for my electronics 101 question posted by MMB on October 26, 2006 at 06:36:24:

The field current of 3.8 Amps to 4 Amps would be at the generator's MAXIMUM output. For MAX output, the resistor is switched OUT of the field circuit by the light switch.

With the resistor IN the circuit, at the generator's low output, likely the field current will be only a couple of Amps.

Watts = I2 X R.

2 Amps squared = 4 X the resistance of 3.3 Ohms = a power dissipation of 13.2 Watts.

Even at a field current of only 1.5 Amps, the resistor would have to dissipate nearly 7.5 Watts.

Even that would likely be too much for all-day sustained operation, with the resistor in the enclosed switchbox.

Better go back to the electronics supply and get a 20 or 25 Watt unit.

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