Re: Tractor H,P./ torque

Posted by Jerry/MT on November 18, 2007 at 17:20:25 from (206.183.116.129):

In Reply to: Tractor H,P./ torque posted by SDE on November 17, 2007 at 18:35:58:

At constant horsepower, the product of torque x rpm = a constant i.e Tengine x Nengine = Tpto x Npto. this is an ideal relation shipt that assume no loss through the gears. So if the engine torque is 472lb-ft at 2000 rpm and the pto is running at 540 rpm when the engine is running at 2000 rpm then the pto torque is:
T2 = T1 x Ne/Npto

472lb-ft x 2000/540 = 1748 lb-ft

If the gear train has an efficency of say 90 % than Tpto actual =efficiency x Tpto i =0.9 x 1748 = 1573 lb-ft.

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