Posted by ScottyHOMEy on August 09, 2008 at 05:53:41 from (70.105.231.176):
In Reply to: What does posted by superpunchy on August 09, 2008 at 02:31:17:
A horsepower-hour is equivalent to 745.7 watt-hours or to use a more familiar measure 0.7457 of a kilowatt-hour. Dividing it by the amount of fuel used to produce it gives you a measure of efficiency.
Put a motor on a dyno so you know it's output, and multiply that by the length of a given run in hours. That's your horsepower-hours for your calculation. Dividing that by the amount of fuel consumed on the same run gives you a measure of efficiency, hp-hrs/gal.
In the electrical analogy, a generating station might gauge the thermo-mechanical efficiency of it various types of standby (peak-hour) generators by comparing the kilowatt-hours produced by a diesel driven generator using gallons of diesel fuel used, or in the case of a gas turbine, cubic feet of gas consumed. There is also a conversion from hp or watt-hours to BTUs, so in essence they are looking for the highest (most efficient) ratio of BTUs in to BTUs out. The BTUs available per unit of either fuel would be known, so they might convert the fuel volume to BTUs to gauge thermo-mechanical efficiency, but in economic terms they might also plug in the cost per BTU of each type of fuel, and decide which generator to spin up first on that basis.
Nebraska was simply developing the same data for the purpose of comparing the efficiency of various tractors.
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