Posted by Ken miller on April 26, 2011 at 19:09:26 from (66.249.229.38):
In Reply to: OT electrical ?? posted by teddy52food on April 26, 2011 at 10:53:20:
In response to the 10 mile loop of wire example. Yes you are basically correct however, it is not an issue of what goes in at point "a" and what comes out at point "c". In your example the wire is simply acting as a resistor which is dissipating 1000 watts of power in the form of heat. Since no work is being performed the 1000 watts is all dissipated in the form of heat. To determine the power input the voltage is measured across point "a" and "c" and the current is constant along the wire. The power is calculated from the product of volts x amps and must equal 1000 in your example. Yes, you are correct there is line loss, the loss is 1000 watts all in the form of heat. In the case of winding the 10 miles of wire into a coil, again the loss would be 1000 watts, all in the form of heat. In both cases the wire will become warm however, 10 miles of wire in free air dissipating a small amount of power will not become warm to the touch. You are correct in that there con not be a gain or loss however, your statement, "the heat and power out is equal to the power going in", is misleading. The heat and power out is one and the same and equal to 1000 watts, all lost in the form of heat. In summary, the power input is 1000 watts of electrical energy which is equal to the 1000 watts of power dissipated in the form of heat.
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