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What I'm hearing is ...and what about weight

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Bill Darte

06-09-2006 09:31:07

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So, what I'm hearing is it would be safer (on the hillside) to have a smaller (5ft.) and lighter (light duty) mower, though it wouldn't be as productive or get as good a cut (tracks coverage).

I don't care much for how perfect a cut job it does, 'cause it is a real mess now.

So, I have NO weights on the front of the tractor and the tires are not filled either.

I was planning on putting a homemade bumper on the front that I could add a box for carrying weight and/or tools in. Should I plan for as much weight up front as the mower weighs? This weight helps counter balance the implement when lifted right...and keeping the front down when mowing up-hill?

When going UP a fairly steep grade, I assume I would want the mower on the ground right?

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Jerry/MT

06-09-2006 11:09:28

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Re: What I'm hearing is ...and what about weight in reply to Bill Darte, 06-09-2006 09:31:07

No you don't want to put as much ballast on as the mower weighs becasue you'll over weight it and possibley damage something.
The center of gravity of the mower is in front of the gear box. Just how far depends on the mower and the 3 point attachment but I'd say a round number would be 6 inches. Measure the distance between a point 6 inches in front of the center of the gear box to the center of the rear axle. Multiply that distance by the weight of the mower (for example a 1100 lb mower and a 3.5 ft distance from the point 6 inches in front of the center of the gear box to the rear axle would give you 3850 ft lbs (1100lb x 3.5 ft). Measure the distance between the rear transmission flange and the center of the rear axle. (I assumed that's where the tractor center of gravity is, it might be closer to the center of the tranny but you can do the calculations both ways to see what the diffference is.) Lets say it's 1 ft. Knowing the weight of your tractor (lets say it's 3000 lbs.) Now measure from the center of gravity of your ballast to the center of the rear axle(lets say that distance is 6 ft.
then (6 xWb) + (3000 x 1) =1100 x 3.5.
Wb (the weight of added ballast)= (3850 -3000)/6 = 142 , which says that you have to add 142 lbs of ballast AND ballast carrier, to zero out the moment of the mower weight.

Usually the mower will have a flex link at the top link connection that allows for some rotation about draft links so when wou go up or down hill the mower is on the ground. It will not cover severe departure angles however so you need to watch out for really severe up and down grade changes.
The weights are just WAGS (wild ... guesses)so you'll have to do someresearch to do it right, just don't overload the tractor.

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