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Behind the eight (volt) ball
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Posted by Fred Martin on January 20, 2000 at 16:10:02 from (208.32.116.17):
Hi all from Fred Okay, first off, go easy on the flack fellers cause I'm a light weight. But I don't think I found out how to charge an eight volt battery on the posts a couple of weeks ago. I didn't get in that heated controversy and I don't want to start it all over again. So, I don't have a degree in electrical engineering, an advanced ham license is my only claim to fame in electronics and that takes quite a bit of theory. (As some may know). The charger doesn't have 8 volts so lets use 12 volts with a series dropping resistor. We'll call the high voltage 14.4 and the low voltage 9.6 volts. Formula for voltage drop is: hi voltage minus low voltage over current. (Remember Ohm's Law). (We'll call the current 10 amps) This means we need about a half ohm resistor in series with one leg of the charger. After checking, I found that a 12 volt #1157 bulb was about right (ohms wise). This would probably light the bulb pretty good when the battery is charging and dim as battery is charged up and limit the amount of current going into battery. I don't have an 8 volt battery, so I didn't try this. Some of you ambitious fellers can work it out and market it if you want, it's needed. But you have to give all us tractor guys and gals a freeby on what the dropping resistor is. Incidentally, everything I read in that post was true (to me) but as the man said "its dangerous". Lets find a safe way. Fred from the Mung Factory
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